lmoleary5135 lmoleary5135
  • 07-03-2018
  • Mathematics
contestada

what are the approximate solutions of 2x^2-x+10=0? f) -2,2.5 g) -1.97,2.47 h)-2.5,2 i) no solution. help me please. :*

Respuesta :

W0lf93
W0lf93 W0lf93
  • 13-03-2018
To solve this problem, Uuse the quadratic equation:  
(-b +/- sqrt(b^2 - 4ac))/2a, 
 where 
 a = 2
 b = -1
 c = 10 
 Solve: 
 (1 +/- sqrt(1 + 4*2*10))/4 
 (1 +/- 9)/4 
 The two solutions are  
 10/4 = 2.5
 (1-9)/4 = -2. The correct answer is f.
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