Answer: 1.66 atm
Data:
P = ?
V = 6.00 liter
n1 = 0.127 mol of H2(g)
n2 = 0.288 mol of N2(g)
T = 20.0°C
Formula:
PV = n RT
Solution:
1) Conversion of units:
= 20 + 273.15 K = 293.15 K
2) n = n1 + n2 = 0.127 mol + 0.288 mol = 0.415 mol
3) PV = nRT => P = nRT / V
R = 0.0821 atm*liter / (K*mol)
P = 0.415 mol * 0.0821 atm * liter / (K*mol) * 293.15 K / 6 liter = 1.66 atm
Answer: 1.66 atm
