dragonladyjo2053 dragonladyjo2053

09-12-2017
Chemistry

contestada

Calculate the temperature, in k, of 2.20 moles of gas occupying 3.30 l at 3.50 atm.

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kenmyna kenmyna

19-12-2017

From idea gas equation that is PV=nRT
T= temperature in kelvin
R=gas cosntant(0.0821atm/k/mol)
P=pressure(3.5atm)
V=volume 3.30L
n=number of moles (2.20mole)
T is therefore =PV/nR
T={(3.50 x3.30) /(2.20 x 0.0821)}=63.95k

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