23)
2(5-3x)<x-4(3-x)
distribute 2 to 5 then 2 to 3x and get 10 - 6x then go on the right side and distribute the -4 to the 3 = -12 cancel out both x since one is negative and ones positive. which is 10 - 6x < -12
subtract 10 on each side and divide by 2
10-10= 0 -12 - 10= 22 divide by 2 is 11 x=11 do that with the other one also
