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  • 08-09-2022
  • Mathematics
contestada

help me please
(2a+3)(3a-4)

Respuesta :

237368 237368
  • 08-09-2022

Answer: 6[tex]a^{2}[/tex]+a-12

Step-by-step explanation:

First, you want to distribute (2a+3)(3a-4) ---> 2a(3a-4) + 3a(3a-4)

That will get you 6[tex]a^{2}[/tex]-8a+9a-12

Next, you will want to combine like terms to get 6[tex]a^{2}[/tex]+a-12

Since you cannot simplify that any further, 6[tex]a^{2}[/tex]+a-12 is your answer.

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