achusuresh2007 achusuresh2007
  • 09-08-2021
  • Mathematics
contestada

factorize 27a³-b³-1-9ab

Respuesta :

manamoto13 manamoto13
  • 09-08-2021

Answer:

Hope this helps!

Please see through the steps below

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mhanifa
mhanifa mhanifa
  • 09-08-2021

Answer:

Use the following identity:

  • a³ + b³ + c³ - 3abc = (a + b + c)(a² + b² + c²- ab - bc - ca)

Apply to the given:

  • 27a³ - b³ - 1 - 9ab =
  • (3a)³ + (-b)³ + (-1)³ - 3*3a*(-b)(-1) =
  • (3a - b - 1)(9a² + b² + 1 + 3ab - b + 3a)
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