aminthing2
aminthing2 aminthing2
  • 10-07-2021
  • Mathematics
contestada

tan^2 theta - cot^2 theta = sec^2 theta (1-cot^2 theta)​

Respuesta :

jessmzhou4
jessmzhou4 jessmzhou4
  • 10-07-2021

Answer:

Based on two Pythagorean Identities:

  • 1 + tan²θ = sec²θ
  • 1 + cot²θ = csc²θ

sec²θ(1 - cot²θ)

= sec²θ - sec²θ · cot²θ

[tex]=\frac{1}{cos ^{2} \theta} -\frac{1}{cos ^{2}\theta }*\frac{cos ^{2}\theta}{sin^{2} \theta}\\\\=\frac{1}{cos ^{2}\theta }-\frac{1}{sin^{2}\theta }\\\\=sec^{2}\theta-csc^{2}\theta\\\\=1+tan^{2}\theta-(1+cot^{2}\theta)\\\\=1+tan^{2}\theta-1-cot^{2}\theta\\\\=tan^{2}\theta-cot^{2}\theta[/tex]

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