Answer:
[tex]a = (b + c)/(2 * c)[/tex]
[tex]z = x/(y + c)[/tex]
[tex]c = (9 * c + 32)/5[/tex]
Explanation:
Required
The expression in basic
To do this, we use () to group items, / as divide and * to combine factors
So, we have:
[tex](a)\ a = \frac{(b + d)}{2c}[/tex]
In basic, it is:
[tex]a = (b + c)/(2 * c)[/tex]
[tex](b)\ z = \frac{x}{y + c}[/tex]
In basic, it is:
[tex]z = x/(y + c)[/tex]
[tex](c)\ c = \frac{9c + 32}{5}[/tex]
[tex]c = (9 * c + 32)/5[/tex]
