Answer:
0.052 M.
Explanation:
Hello!
In this case, since the molarity is computed by dividing the moles of the solute by the volume of the solution in liters (M=n/V), we first need to compute the moles in 5.025 grams of NaOH as shown below:
[tex]n=5.025g*\frac{1mol}{40.0g}\\\\n=0.126mol[/tex]
In such a way, we compute the molarity as show below:
[tex]M=\frac{0.126mol}{2.4L}\\\\M=0.052M[/tex]
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