Answer:
[see below]
Step-by-step explanation:
[tex]w=5(3a-b)+2\\\\w-2=5(3a-b)+2-2\\\\w-2=5(3a-b)\\\\\frac{w-2=5(3a-b)}{5}\\\\\frac{w-2}{5} =3a-b\\\\\frac{w-2}{5} +b=3a-b+b\\\\\frac{w-2}{5} +b=3a\\\\\frac{\frac{w-2}{5} +b=3a}{3}\\\\ \frac{w-2+5b}{15}=a\\\\ \boxed{a= \frac{w-2+5b}{15}}[/tex]
Hope this helps.
