Answer:
[tex]\bold{y-12\,=\,-\dfrac13(x-7)}[/tex]
Step-by-step explanation:
The "point-slope" form of the equation of a straight line is:
[tex]y-y_p=m(x-x_p)[/tex]
[tex](7,\,12)\quad\implies\quad x_p=7\,,\quad y_p=12\\\\m=-\dfrac13[/tex]
So:
[tex]\bold{y-12\,=\,-\dfrac13(x-7)}[/tex]
