Respuesta :

dannielle

Answer:

Step-by-step explanation:

4*3^x+1=27+(3^2)^x

(3^2)^x=(3^x)^2

3^x=t

4t+1=27+t^2

t^2-4t+27-1=0

t^2-4t+26=0

delta=4^2-4*1*26=16-84=-68<0

the  equation has not real solutions

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