Answer:
[tex]D=-5y^2[/tex]
Step-by-step explanation:
We have the equation:
[tex]\displaystyle -15y^4=D(3y^2)[/tex]
And we want to find D such that the equation is true.
So, we can divide both sides by 3y². This will yield:
[tex]\displaystyle D=\frac{-15y^4}{3y^2}[/tex]
We can split this into:
[tex]\displaystyle D=\frac{-15}{3}\cdot\frac{y^4}{y^2}[/tex]
Simplify. Hence:
[tex]D=-5y^2[/tex]
