Answer:
sec(π/6 - x) = R.H.S = 2/(√3cosx + sinx) = L.H.S.
Step-by-step explanation:
sec(π/6 - x) = 1/cos(π/6 - x)
Using compound angle formula,
cos(A - B) = cosAcosB + sinAsinB where A = π/6 and B = x.
So, cos(π/6 - x) = cos(π/6)cosx + sin(π/6)sinx , cosπ/6 = √3/2 and sinπ/6 = 1/2
cos(π/6 - x) = cosπ/6cosx + sinπ/6sinx = (√3/2)cosx + (1/2)sinx
sec(π/6 - x) = 1/cos(π/6 - x)
= 1/(√3/2)cosx + (1/2)sinx = 2/(√3cosx + sinx)
= L.H.S
So, sec(π/6 - x) = R.H.S = 2/(√3cosx + sinx) = L.H.S
