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07-05-2020
Mathematics

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Factor completely 2x^2+4x-2

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mysticchacha mysticchacha

07-05-2020

Answer:

2x^2+4x-2 = 2 * (x - 1 -[tex]\sqrt{2}[/tex]) * (x - 1 + [tex]\sqrt{2}[/tex])

Step-by-step explanation:

Factor completely 2x^2+4x-2

2x^2+4x-2 = 2* (x^2 + 2x - 1)

x = 1 + root( 4 - 4*(-1))/2

x = 1 + root(2)

and x = 1 - root(2)

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