Respuesta :

dalendrk
[tex]9^{x-2}=27\\\\(3^2)^{x-2}=3^3\\\\3^{2(x-2)}=3^3\\\\3^{2x-4}=3^3\iff2x-4=3\ \ \ |add\ 4\ to\ both\ sides\\\\2x=7\ \ \ \ |divide\ both\ sides\ by\ 2\\\\\boxed{x=3.5}[/tex]
  As we are given the equation
 9^(x - 2)=27
solving
 =3^2(x-2)=3^3
 just equal the basis 
2(x-2)= 3 

x=7/2=3.5
so correct option is D
hope it helps

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