Answer: D
Step-by-step explanation:
[tex]x^2-3x+3=0\qquad \rightarrow \qquad a=1,\ b=-3,\ c=3\\\\\\x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\\x=\dfrac{-(-3)\pm \sqrt{(-3)^2-4(1)(3)}}{2(1)}\\\\\\x=\dfrac{3\pm \sqrt{9-12}}{2}\\\\\\x=\dfrac{3\pm \sqrt{-3}}{2}\\\\\\x=\dfrac{3\pm i\sqrt{3}}{2}\\\\\\\boxed{x=\dfrac{3+ i\sqrt{3}}{2}\qquad \qquad x=\dfrac{3- i\sqrt{3}}{2}}[/tex]
