verYelStolesle
verYelStolesle verYelStolesle
  • 06-07-2016
  • Mathematics
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given the line 2x - 3y - 5 = 0, find the slope of a line that is perpendicular to this line. 3/2 2/3 -3/2

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Ckaranja
Ckaranja Ckaranja
  • 10-07-2016
2x-3y-5=0
2x-5=3y
3y=2x-5
y=[tex] \frac{2}{3} x- \frac{5}{3} [/tex]
Gradient of line 1 = [tex] \frac{2}{3} [/tex]
Gradient of line 2;
[tex] m_{1} * m_{2} =-1[/tex]
[tex] m_{2} * \frac{2}{3} =-1[/tex]
[tex] m_{2} =- \frac{3}{2} [/tex]
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