Answer:
B and D
Step-by-step explanation:
Given
[tex]\frac{x+8}{x^2-2x-24}[/tex]
The denominator of the rational function cannot be zero as this would make it undefined. Equating the denominator to zero and solving gives the values that x cannot be.
Solve x² - 2x - 24 = 0, that is
(x - 6)(x + 4) = 0
Equate each factor to zero and solve for x
x - 6 = 0 ⇒ x = 6 → B
x + 4 = 0 ⇒ x = - 4 → D
