Respuesta :

laurellee27

Answer:

[tex](x-2)^{2} + (y+3)^{2} = 4[/tex]

Step-by-step explanation:

Formula

[tex]Centre (a,b) \\Radius r(x-a)^{2} + (y-b)^{2} = r^{2}\\\\Centre (2, -3) \\Radius 2(x-(2))^{2} + (y-(-3))^{2} = 2^{2}\\(x-2)^{2} + (y+3)^{2} = 4[/tex]

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