Answer:
[tex]x=2\textrm{ or } x=-\frac{4}{3}[/tex]
Step-by-step explanation:
Given:
The equation is given as:
[tex]3x^{2}-2x-8=0\\3x^{2}-6x+4x-8=0\\3x(x-2)+4(x-2)=0\\(x-2)(3x+4)=0\\\\x-2=0\textrm{ or }3x+4=0\\x-2+2=0+2 \textrm{ or }3x+4-4=0-4\\x=2\textrm{ or }3x=-4\\x=2\textrm{ or}\\x=-\frac{4}{3}[/tex]
Therefore, the possible values of [tex]x[/tex] are 2 and [tex]-\frac{4}{3}[/tex]
