KarressG
KarressG KarressG
  • 10-06-2019
  • Mathematics
contestada

Find the product
(2n-2)(2n^2-3n+5)

Respuesta :

sqdancefan
sqdancefan sqdancefan
  • 10-06-2019

Answer:

  4n^3 -10n^2 +16n -10

Step-by-step explanation:

Use the distributive property to eliminate parentheses, then combine like terms.

  = 2n(2n^2 -3n +5) -2(2n^2 -3n +5)

  = 4n^3 -6n^2 +10n -4n^2 +6n -10

  = 4n^3 +n^2(-6-4) +n(10+6) -10

  = 4n^3 -10n^2 +16n -10

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burrier7445s burrier7445s
  • 12-11-2021

Answer:

(2n + 2)(2n – 2)

= (2n)^2 -2^2

= 4n^2 - 4

hope i helped

Step-by-step explanation:

Answer Link

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