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06-06-2019
Mathematics

contestada

what is the eqaution of a circle with center (2,-10) and radius 3

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Akshatraj377 Akshatraj377

06-06-2019

Answer:

x2+y2−4x+20y+4=0.

Explanation:

The eqn. of a circle with centre (h,k) and radius r is given by,
(x−h)2+(y−k)2=r2.
Accordingly, the reqd. eqn. is,
(x−2)2+(y+10)2=3^2, i.e.,
x2+y2−4x+20y+4=0.

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