Answer:
The area of parallelogram GHTA is [tex]41.568 cm^2[/tex].
Step-by-step explanation:
Given parallelogram GHTA
GH = 8 cm =-AT
GA = 6 cm
∠ GAT =∠ GHT = 60°
To find = Area of parallelogram
Solution:
Draw perpendicular GO on the base AT.
In ΔGOA
[tex]\sin 60^o=\frac{GO}{GA}=\frac{GO}{6 cm}[/tex]
(sin 60°=0.8660)
GO = 5.196 cm
Area of the parallelogram: GO × AT
[tex]=5.196 cm\times 8 cm =41.568 cm^2[/tex]
The area of parallelogram GHTA is [tex]41.568 cm^2[/tex].
