sitaladriannaoz4hgf sitaladriannaoz4hgf
  • 10-04-2019
  • Mathematics
contestada

secxcscx/cotx = sec^2x​

secxcscxcotx sec2x class=

Respuesta :

jimrgrant1 jimrgrant1
  • 10-04-2019

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identities

• secx = [tex]\frac{1}{cosx}[/tex], cscx = [tex]\frac{1}{sinx}[/tex]

• cotx = [tex]\frac{cosx}{sinx}[/tex]

Consider the left side

[tex]\frac{sexcscx}{cotx}[/tex]

= [tex]\frac{1}{cosx}[/tex] × [tex]\frac{1}{sinx}[/tex] × [tex]\frac{sinx}{cosx}[/tex]

Cancel the sinx on numerator/ denominator

= [tex]\frac{1}{cos^2x}[/tex]

= sec²x = right side ⇒ verified

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