Answer:
[tex]4(3\frac{2}{5})[/tex] is greater
Step-by-step explanation:
step 1
we have
[tex]4(3\frac{2}{5})[/tex]
convert to an improper fraction
[tex]3\frac{2}{5}=\frac{3*5+2}{5}=\frac{17}{5}[/tex]
so
[tex]4(3\frac{2}{5})=4(\frac{17}{5})=\frac{68}{5}[/tex]
step 2
we have
[tex]3(4\frac{2}{5})[/tex]
convert to an improper fraction
[tex]4\frac{2}{5}=\frac{4*5+2}{5}=\frac{22}{5}[/tex]
so
[tex]3(4\frac{2}{5})=3(\frac{22}{5})=\frac{66}{5}[/tex]
therefore
[tex]4(3\frac{2}{5})[/tex] is greater
