Answer: [tex]x=-5[/tex]
Step-by-step explanation:
To solve this exercise you need to remember the following:
[tex]e^{lnx}=e^{lny}[/tex] → [tex]x=y[/tex]
Therefore, keeping the above on mind, you can solve for x as following:
[tex]e^0=e^{ln(x+6)}[/tex]
[tex]e^0=x+6[/tex]
Remember that, by definition: [tex]a^0=1[/tex], then you have:
[tex]1=x+6[/tex]
Subtract 6 from both sides of the equation.
Then the value of x is:
[tex]1-6=x+6-6\\x=-5[/tex]
