Answer:
[tex]\large\boxed{x=\dfrac{137}{3}}[/tex]
Step-by-step explanation:
[tex]\text{Use:}\\\\\ln a+\ln b=\ln(ab)\\\\\ln a=\ln b\Rightarrow a=b\\-------------\\Domain:\\\\3x-5>0\qquad\text{add 5 to both sides}\\\\3x>5\qquad\text{divide both sides by 3}\\\\x>\dfrac{5}{3}\\-----------------\\\\\ln(3x-5)=\n11+\ln12\\\\\ln(3x-5)=\ln(11\cdot12)\\\\\ln(3x-5)=132\iff3x-5=132\qquad\text{add 5 to both sides}\\\\3x=137\qquad\text{divide both sides by 3}\\\\x=\dfrac{137}{3}[/tex]
