Answer:
6.7 m/s^2
Explanation:
The acceleration of the firebird is given by:
[tex]a=\frac{v-u}{t}[/tex]
where
v is the final velocity
u is the initial velocity
t is the time taken
In this problem, we have:
[tex]v=60 mph \cdot \frac{1609 m/mile}{3600 s/h}=26.8 m/s[/tex]
[tex]u=0[/tex]
[tex]t=4 s[/tex]
So, the acceleration is
[tex]a=\frac{26.8 m/s-0}{4 s}=6.7 m/s^2[/tex]
