Respuesta :

Answer:

3x-4y+29=0

Step-by-step explanation:

Use this ;

[tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} } = \frac{y-y_{2} }{x-x_{2} }[/tex]

So it'll be;

5+1/5+8 = y-5/x+3 (cross-multiply);

6x-8y+58=0

3x-4y+29=0

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