Respuesta :

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[tex]f(x)=3x+1;\ g(x)=x^2-6\\\\\left(\dfrac{g}{f}\right)(x)=\dfrac{g(x)}{f(x)}\\\\\boxed{\left(\dfrac{g}{f}\right)(x)=\dfrac{x^2-6}{3x+1}}[/tex]

Answer:

Answer: x^2-6/3x+1,x not equal to -1/3

Step-by-step explanation:

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