Answer:
[tex]b = 14[/tex]
Step-by-step explanation:
Given that the modulus of z = 48+bi is 50
Also that the point lies in the I quadrant.
Hence b can be positive only
We have from the definition of modulus of complex numbers that
[tex]|48+bi|=\sqrt{48^2+b^2} \\=50[/tex]
Square both sides to get
[tex]48^2+b^2 =50^2\\b^2 = 50^2-48^2 =196\\b = +14[/tex]
Hence we find that the square root is positive for +14
So [tex]b = 14[/tex] is the answer.
