First, determine the domain: x ≥ 0 (because you can't square root a negative)
Next, square both sides of the equation and solve for "x".
(√x)² < (5)²
+/- x < 25
+x < 25 -x < 25
x< 25 x > -25 ⇒ Remember the domain is x ≥ 0
x < 25 and x ≥ 0 ⇒ 0 ≤ x
Answer: 0 ≤ x < 25 interval notation [0, 25)
