Let the equation of the given line be y=mx+a. This line has slope m and the parallel line will have the same slope.
Then the equation of the parallel line to the line y=mx+a will be y=mx+b. Since line passes through the point (–2, 2), the coordinates of this point suit the equation:
2=m·(-2)+b,
2=-2m+b,
b=2+2m
and the equation is y=mx+2m+2.
You should only to paste correct m from the given equation.
