Respuesta :

gmany
[tex]8x^2+16x+8=0\\\\8(x^2+2x+1)=0\ \ \ |:8\\\\x^2+2x+1=0\\\\x^2+x+x+1=0\\\\x(x+1)+1(x+1)=0\\\\(x+1)(x+1)=0\\\\(x+1)^2=0\iff x+1=0\\\\\boxed{x=-1}[/tex]
Answer: B. -1